
Question #e395e - Socratic
Feb 11, 2016 · When decaying by alpha emission a nucleus drops by 4 in mass number and 2 in atomic number and emits a helium nucleus (alpha particle) which has mass number 4 and atomic number 2. …
James and Kathryn together had $190 in a savings bank. The ... - Socratic
James and Kathryn together had $190 in a savings bank. The amount in James's account was $30 more than 3 times the amount in Katherine's account. How much had each? Algebra
Question #9c6af - Socratic
"3.2 mol kg"^(-1) In order to be able to calculate the molality of the solution, you need to know the number of moles of solute present for every "1 kg" = 10^3 "g" of solvent. In your case, you know that …
Some very hot rocks have a temperature of 190 ^o C and a ... - Socratic
Some very hot rocks have a temperature of #190 ^o C# and a specific heat of #90 J/ (Kg*K)#. The rocks are bathed in #270 L# of boiling water. If the heat of the rocks completely vaporizes the water, what …
What are the mean and standard deviation of a binomial probability ...
What are the mean and standard deviation of a binomial probability distribution with #n=190 # and #p=7/11 #?
Find the exact soultions on the interval from (-90degrees ... - Socratic
Find the exact soultions on the interval from (-90degrees, 720degrees) cos3x=-sqrt3/2?
How do you simplify t^ { \\frac { 13} { 5} } \\cdot t ^ { \\frac { 11 ...
Oct 14, 2017 · t^ (38/7) t^ (15/5)*t^ (11/7) =>t^ (15/5+11/7) =>t^ (135/35+55/35) =>t^ (190/35) =>t^ (38/7)
Question #da1ce - Socratic
Dec 6, 2015 · #190 * color (blue) (T_"f") - 3800 = -1470 * color (blue) (T_"f") + 117600# #1660 * color (blue) (T_"f") = 121400 implies color (blue) (T_"f") = 121400/1660 = 73.13^@"C"# Now, you should …
What is the mass of 211mL of a liquid that has a density of ... - Socratic
Approx. 190*g... By definition, rho, is given by the quotient.... rho_"density"="mass"/"volume", and thus has units of g*mL^-1-=g*cm^-3... And so we simply rearrange ...
How do you solve this system of equation: 6x - Socratic
Explanation: #6x-10y=2# #-9x-2y=16# from first equation #x= (10y+2)/6# sub into the second #-9 ( (10y+2)/6)-2y=16# #-102y=114# #y=-19/17#